Tag: can you convert digital audio to rca

Free Download Mp4Gain

Know the “bit rate”

Which is important in determining the amount of video data and image quality.

This time, we will learn about “bit rate” which is one of the important factors in determining the image quality of video.

It is closely related to this article, but you can learn more about video screen resolutions and frame rates in another article.

If you are unsure, I recommend reading the article on screen resolutions and frame rates before reading this article.

Points to consider when deciding the frame rate (fps) of a video
The optimal resolution of the video screen is not always Full HD! Consider the screen resolution of the video.
Table of Contents
What is a bit rate?
Relationship between screen resolution, frame rate, and bit rate
Based on the above, let’s consider the relationship between resolution / frame rate, amount of data, and bit rate.
What to do to improve image quality
Consider the optimal resolution, frame rate, and bit rate for each type of content.
Points for building a video distribution service Free distribution
Video Recording and Live Distribution Guide You Can Do In-House for Free

What is a bit rate?
Bit rate is expressed in bps.
Short for bits per second, which indicates how many bits of data a video creates per second.
For example, a 1 Mbps video will have 0.125 megabytes of data per second. It will be 7.5 MB in 1 minute.
As with screen resolution and frame rate, you can decide what bit rate you want.

Since 8 bits are 1 byte, it becomes “1 Mbit ÷ 8 = 0.125 Mbyte”.
Relationship between screen resolution, frame rate, and bit rate
Let’s review a bit.

The screen resolution indicates the height of the number of pixels in the video.
The frame rate shows how many images a video is made up of per second.
Bit rate represents the amount of data per second.

Based on the above, let’s consider the relationship between resolution / frame rate, amount of data, and bit rate.
4K resolution is four times the area of ​​Full HD, so more data is required to draw.
Since video at 60fps has twice as many frames as at 30fps, more data is required to draw.

for instance

If you want to make a “1Mbps in Full HD / 30fps” video with the same image quality in “4K / 60fps”

Resolution area 4 times x frame rate 2 times = 8 times

The amount of data required is required and in theory 8Mbps is a guide.

However, as mentioned above, the bit rate can be set arbitrarily, so it is also possible to make “1Mbps video at 4K / 60fps”.

It makes no sense to convert a Full HD / 30fps video into a 4K / 60fps video.
Even if you double the number of 30 videos per frame to 60, the same image will continue for 2 frames and the number of frames will be wasted.
Similarly, when it comes to resolution, it doesn’t make sense to stretch what originally only had Full HD resolution to 4K.
Therefore, it is a good idea to prepare the video that will be the material to create video content with the highest resolution and high frame rate possible. It is not wasted when converted to a lower number.
If you’re not ready, don’t forget to set the resolution and frame rate below the footage video.
What to do to improve image quality
It turned out that the higher the resolution and the bit rate, the better the video can be drawn without using a lot of data.

So to improve image quality, should the bitrate be increased anyway?
This is not bad, but the article on screen resolutionBut the same thing that I wrote will happen.
In other words, the higher the bit rate, the larger the file size.
If the file size is large, the transfer of video data to the viewer will be slow, and in the case of smartphones, the monthly data traffic will soon disappear.

With that in mind, we need to find the best bit rate.
When sending videos over the Internet, the lower the amount of data, the better.
The correct answer is to aim for a video with a small amount of data and sufficient image quality.

Next, I prepared two videos of the same video with different bit rates. See how the image quality changes with the bit rate.

Free Download Mp4Gain


Mp4Gain Main Window


Mp4Gain Features


Free Download Mp4Gain

Relationship between kHz and bit

Use an audio interface when recording live sound to your DAW. At this time, the A / D converter converts analog to digital
and kHz or bits are used during this conversion process.

Let’s take a look at the following figure. It is analog, so of course it is continuous.

Analog input waveform
When
converted with low kHz (sampling frequency) and low bits (speed), it becomes as shown in the figure below.

Waveform after digital recording Low sample rate
The prototype of the original sound of the original is somehow preserved.
When converting with a high sample rate and bit rate, it will be as shown in the figure below.

Waveform after digital recording High sampling frequency
It is close to the original waveform.

The
Above figure shows the difference between low sample rate and low bit rate and high sample rate and high bit rate.

Now about the sample rate and bit rate.

The sampling rate, also known as “sampling”,
represents how many times it is sampled per second.

The bit rate, also known as “quantization”,
indicates how many steps the loudness is reproduced from silence to maximum volume.

The following figure is the picture. The apparent difference between “16 bit and 24 bit” is 24-16 = 8, but in reality there is a stage difference of 16,777,216 steps-65,536 steps = “16,711,680 steps”. The difference between 16-bit and 24-bit is actually 256 times.
16-bit 44.1 kHz recording
24-bit 48kHz recording

By the way, the sampling frequency is 48 kHz ÷ 44.1 kHz = 1,088 times.

It makes no sense to judge sound quality by numbers, but
I think the relationship between sample rate and bitrate is not negligible difference.

Another thing related to sound is the “standards / features”.

Audio CDs are created at 44.1 kHz, 16-bit, but as the response of
frequency is 20 Hz to 20 kHz, to be precise, the sound
between 20 Hz and 20 kHz it is sampled 44,100 times per second and
volume is 65,536. What we record on stage is the
“CD” we are listening to.

By the way, the bit rate is 1411.2 kbps.

Just a bit for reference on the ability to generate data.
Information such as headings and labels is actually added, so it will be a bit larger.

Taking WAV as an example,
data size = sample rate (Hz) x number of bits x number of channels x time (seconds)
1 second stereo sound source (2ch) recorded at 44.1 kHz, 16-bit

When converted to WAV,
44,100 (Hz) x 16 bits x 2 channels x 1 second = 1,411,200 bits
Byte conversion = 1,411,200 bits ÷ 8 = 176,400
Byte Conversion KB = 176,000 Bytes ÷ 1024 = 172KB

One second of WAV data is 172 KB.

So how many minutes of WAV data can you burn to a CD-R?

CD-R 650 MB = 665,600 KB ÷ 172 KB (1 second) =
Converted to 3869 seconds = 3869 seconds ÷ 60 = 64 minutes

The time that WAV can be recorded on a CD-R in data format is 64 minutes.
* The recording time in CD-DA format and the recording time in WAV data
differ depending on the recording format.

Reference:
1Byte = 8bit
1KB = 1024byte
1MB = 1024KB = 1,048,576Byte
1GB = 1024MB = 1,073,741,824Byte
1TB = 1024GB = 1,099,511,627,776Byte

As always,
I think there may be minor errors in the omission of rounding in the calculation and the content of the explanation, but please understand it at the OK level if it is approximately correct.

Sampling rate

The sample rate is an index for converting analog data such as speech into a digital signal and indicates how many times a sample of information is measured per second.

The unit is Hertz (Hz). Also called “sample rate” or “sample rate.” In most security cameras and surveillance camera systems, recording is done using the linear PCM method. The quality of recorded audio is highly dependent on the sample rate (Hz) and bit rate (bps / bit), but the amount of data is overwhelmingly less than that of motion pictures, so if you are concerned about the balance between quality and quantity of data It can be said that there is no such thing.

On the other hand, the standard for general music CDs was decided in the early 1980s, and the sample rate is 44.1 kHz and the bit depth is 16 bits. In other words, 1,411,200 bits of information are recorded per second. If this is converted to 60 minutes, it will be converted to 5,080,320,000 bit data ≒ 635 MB (megabytes). This is called uncompressed linear PCM recording, but of course the data capacity is too large in the uncompressed state, so when recording with a security camera or surveillance camera, this data is compressed and they record. The amount of data is compressed to approximately 1/10 to 1/30 by processing such as lossy compression that removes data that is outside the human audible range.

This is the only analog term you should know

Sampling rate

The sampling rate is the number of sampling processes performed per second in an A / D converter that converts an analog signal into a digital signal. Also called sample rate, sample rate, or sample rate. The unit is sample / second (sps) or Hz.

A / D converters have two crucial functions. One is resolution. The other is this sample rate. The resolution represents the precision of the conversion in the direction of the voltage axis (vertical axis) and the sample rate represents the precision of the conversion in the direction of the time axis (horizontal axis). Therefore, the higher the performance (the higher the performance), the better the performance.

Input signals of fs / 2 or less can be sampled
Higher sample rates allow faster analog input signals to be converted to digital values. However, there is a limit to the frequency of the analog input signal that can be converted. If the sampling frequency is fs, the frequency that can be sampled is fs / 2. Below this frequency, it is possible to restore the original analog input signal after sampling. This relationship is called the sampling theorem (sampling theorem) and the frequency of fs / 2 is called the Nyquist frequency.

What sample rate do you need? It depends on the application the A / D converter is applied to. For example, tens of k to several M samples / sec (Hz) for audio equipment, tens to hundreds of M samples / sec (Hz) for audio processing equipment. pictures and tens to several G samples for communication equipment. The A / D converter is used for / sec (Hz), several k to several M samples / sec (Hz) for high precision measuring instruments, and several tens of M to several G samples / sec (Hz) for measuring instruments. Of high speed.

Currently, as a high-speed A / D converter, an IC with a high sampling rate of several Gsample / sec is marketed. For example, Texas Instruments (TI) “ADC12D1800RF”. The resolution is 12 bits. It integrates two A / D converters with a high sampling frequency of 1.8 Gsample / sec. By interleaving (time division) operation, it can be used as a 3.6 Gsample / sec A / D converter, and also as a dual A / D converter operating at 1.8 Gsample / sec. For broadband communication equipment, radar equipment, test / measurement equipment, etc.

The problem of finding the length of recordable audio

Audio is sampled 11,000 times per second, and each sampled value is recorded as 8-bit data.

At this time, what is the maximum length of audio that can be recorded in flash memory with a capacity of 512 x 10 6 bytes?

A 77 B 96 C 775 D 969

Next is the question of finding the length of audio that can be recorded. With the knowledge acquired so far, you can easily find a calculation method. The way of thinking when calculating is shown below.

Since 11000 samples are taken per second and each one is recorded as 8 bits = 1 byte of data, the amount of data per second is 11000 x 1 = 11000 bytes.
Since the capacity of the flash memory is 512 x 10 6 bytes, data of 512 x 10 6 ÷ 11000 = 46545.45 … seconds can be recorded.
Since the answer is obtained in minutes, 46545.45 … ÷ 60 = 775.75 … minutes.
Since the question says “maximum number of minutes”, the maximum is 775 minutes rounding down the fraction of 775.75 …, and option c is the correct answer.

correct answer hare

Problem finding the sampling interval
Question 4 (Fall 2016)
When the audio was sampled using the PCM method, converted to 8-bit digital data and transferred in real time without compression, the transfer rate was 64,000 bits / sec. How many microseconds is the sampling interval at this time?

A 15.6 B 46.8 C 125 D 128

Now the question is to find the sampling interval (how many seconds to sample).

The “transfer rate” is involved, but since the audio was transferred in real time, 64000 bits / second is the same as the encoded capacity per second. Once you know that, you will be able to find a calculation method with the knowledge you have gained so far.

The way of thinking when calculating is shown below.

Since there are 64000 bits per second and the size of the encoded data is 8 bits, the number of samples taken per second is 64000 ÷ 8 = 8000 times.
Since 8000 samples were taken per second, the time interval is 1 ÷ 8000 = 0.000125 seconds.
Since the question is “how many microseconds?”, The correct answer is 125 microseconds, which is 0.000125 seconds in microseconds.

correct answer hare

Problem finding buffering time
Q31 (Fall 2014)
To play 2.4 Mbytes of audio data at 192 kbit / s encoding speed without interruption during downloading using a network with 128 kbit / s communication speed, buffering the data before the start of playback How many seconds do you need in less?

A 50 B 100 C 150 D 250

Finally, let’s fix an issue with a slightly different coat color. Finding the buffering time when downloading digitized audio data is a problem.

Buffering is downloading some data before starting to play. This allows you to play the audio without interruptions, even if the download speed is slow.

The idea when calculating is shown below, so please check each one carefully. Here, M = 1000 k.

A code rate of 192 kbits / s means that the amount of digitized data is 192 kbits per second.
The total amount of data is 2.4 Mbytes = 2.4 M x 8 = 19.2 M bits, which is expressed in seconds as 19.2 M ÷ 192 k = 19200 k ÷ 192 k = 100 seconds.
Since the communication speed is 128 kbit / s, data of 128 k x 100 = 12800 kbit can be transferred in 100 seconds.
However, since the total data capacity is 19.2 Mbit = 19200 kbit, the difference of 19200 kbit – 12800 kbit = 6400 kbit of data must be buffered beforehand.
Since the communication speed is 128 kbit / s, it takes 6400 k ÷ 128 k = 50 seconds to buffer the 6400 kbit data.
From the above, the buffering time is 50 seconds and option A is the correct answer.

Sampling, quantification, coding

The computational problem of voice sampling is to convert analog data (smooth and continuous data), such as raw speech and music, into digital data (discontinuous and discontinuous data) that can be processed by a computer.

In a familiar example, music recorded on a CD (compact disc) is analog data converted to digital data.
Aim to solve speech sampling computational problems, to understand the term “sampling”, “quantization”, “encoding”. Let’s use a general CD as an example to explain the meaning of each term.

What is “sampling”?
It consists of collecting data from analog signals by dividing them at regular time intervals. This time interval is called the “sample rate” and is expressed in units of Hz (Hertz). Once per second is 1 Hz.
The sampling frequency of the CD is 44.1 kHz (kilohertz) and the data is collected 44.1 x 1000 = 44100 times per second.
What is “quantification”?
It consists of converting the data collected by sampling into numerical values. The magnitude of this number is called the “quantization bit number”.
The number of quantization bits on a CD is 16 bits (16 digits in binary).
What is “encode”?
It consists of putting the numerical value obtained by quantification in a specific format. The “PCM (Pulse Code Modulation)” format encodes 16-bit quantized data in its original form.
Once you understand the meaning of the terms, as an example of the calculation, the amount of data when digitizing music with a 5-minute playback time at 44.1 kHz sample rate, 16-bit quantization bit number, PCM format, stereo (2ch), Let’s find it in units of M-byte (megabyte). Here, 1 Mbyte = 1,000,000 bytes. The way of thinking when calculating is shown below.

It is just a multiplication, but understand the method of calculation by associating it with the meaning of the term.

Five minutes of playing time is 5 x 60 = 300 seconds.
Since the sample rate is 44.1 kHz, the data is collected 44.1 x 1000 = 44100 times per second.
Therefore, the data is collected 300 x 44,100 = 13230,000 times in 5 minutes.
The number of 16-bit quantization bits is 8 bits = 1 byte, so 16 bits = 2 bytes.
Since it is in PCM format, this 2-byte data is converted to the code as is.
Since a data collection is a 2-byte code, 13230,000 data collections have a capacity of 2 x 13230000 = 26460000 bytes.
Since it is stereo (2 channels), there are two data of the same capacity (one for the left channel and one for the right channel), and the total capacity is 26460000 x 2 = 52920000 bytes.
Since 1 Mbyte = 1,000,000 bytes, 5,292,000 bytes = 52.92 Mbytes.
PR
The problem of finding the amount of data
Q26 (Spring 2012)
If a 60-minute (monaural) audio signal is digitized using the PCM method with a 44.1 kHz sample rate and 16-bit quantization bit rate, how many Mbytes of data are there? Here, the data is assumed to be uncompressed.
A 80 B 160 C 320 D 640

Let us now solve the above problem of speech sampling. The first is a problem that can be solved with the same procedure as in the calculation example shown above. The way of thinking when calculating is shown below.

M (mega) can be 1000 x 1000 = 1000000 or 1024 x 1024 = 1048576, which is not shown in this number. Here, it is calculated as 1,000 x 1,000 = 1,000,000.

The audio signal for 60 minutes is 60 x 60 = 3600 seconds.
Since the sample rate (sample rate) is 44.1 kHz, the data is collected 44.1 x 1000 = 44100 times per second.
Therefore, 3600 x 44100 = 158760000 times of data collection in 60 minutes.
The number of quantization bits is 16 bits, which is 8 bits = 1 byte, so 16 bits = 2 bytes.
Since it is in PCM format, this 2-byte data is converted to the code as is.
Since a data collection is a 2-byte code, data collections 158760000 have a capacity of 2 x 158760000 = 317520000 bytes.
Being monaural (not stereo), the total capacity is 317520000 bytes.
Given that 1 Mbyte = 1,000,000 bytes, 317520000 = 317.52 Mbytes.
Since the question says “how many Mbytes?”, The correct answer is 320 Mbytes, which is close to 317.52 Mbytes.

Sampling rate

In the separate article “Bit rate and bus width” and “Notes on reducing the bit rate”, we presented the history of the “bit rate”, which is the vertical axis of graph paper during PCM sampling.

This section considers the “sample rate” of the horizontal axis.

Maximum frequency that can be sampled (Nyquist frequency)

With the PCM method, exactly half the sample rate is the maximum recordable rate. This value is also called the “Nyquist frequency”.
For CDs recorded at a sampling frequency of 44.1 kHz, half, 22.05 kHz, is the theoretical maximum recordable frequency.

Now half the sample rate is the maximum recordable rate, and the reason is … Seeing is believing, see the figure to the right.
To represent a cycle of a sine wave, you must draw up and down round trips using at least two samples.

Alias ​​noise: frequencies higher than recordable

But what if a signal with a frequency higher than the Nyquist frequency enters the A / D converter?

See the graphic to the right.

While the input signal performs “3 round trips with 4 samples”, the resolution of the horizontal axis (measurement frequency) of the A / D converter is too low to correctly follow the movement of the signal. The sampled values ​​draw a “one round trip with four samples” waveform, which is significantly lower than the input frequency. Once again, the original signal is “manufactured” in the digital domain.

In this way, an input signal with a frequency higher than the Nyquist frequency is the source of a signal with a lower frequency than it should be, called “alias noise.”

Alias ​​noise is also called “envelope noise” because it occurs at a frequency lower than the Nyquist frequency by the amount that the original signal exceeds the Nyquist frequency, as shown in the graph to the right. The alias noise that wraps around and reaches 0Hz continues to be wrapped between 0Hz and the Nyquist frequency so that it is reflected back.

Actually, the A / D converter contains a low pass filter to prevent such alias noise, so alias noise is not a problem when recording analog signals.

However, handling alias noise can be important when using plugins. The next section explains this point.

Do you need a high sample rate?
When starting to record or compose with a DAW, how to set the sample rate of the project is a difficult place. Unlike the bitrate above, once the sample rate is set, it is difficult to change it later.
It is generally said that the higher the sample rate, the higher the quality of the master that can be produced without damaging the original sound, but the PC specs required during work will also improve dramatically.
But is there any merit in editing at a high sample rate, like when the final medium is a 44.1 kHz CD? Also, can you ignore the difference in sample rate based on the trend of the sound you are looking for, such as the genre you are dealing with?

The bottom line is that when you use harmonic effects like saturators and compressors in your DAW, the sample rate setting can have a significant effect.

Next, we’ll use an ultrasound to consider how the project’s sample rate will change.

The first is a single scan signal sonogram. You can see that the frequency of the sine wave gradually increases from 0 to 22 kHz.

Let’s add a distortion effect to this.
In each case, the signal with the effect applied is exported in projects with different sample rates, and then the file is converted to 44.1 kHz.
All effects use the same preset.
Note that the files themselves that are comparing sonograms are all 44.1 kHz.

Sample, sample rate, sample format, and bit rate

The main function of the audio interface is to convert the signal between analog and digital formats.

As mentioned above, real sounds have endless possibilities for pitch, volume, and duration. Computers cannot process infinite information, so audio signals must be converted before they can be used.
Computer approximated waveform
Source: pcm.svg http://commons.wikimedia.org/wiki/File:Pcm.svg Retrieved from.
Figure 1.1 Computer approximated waveform

The figure in Figure 1.1, “Computer approximated waveforms” illustrates the situation. The red waveform shows the sound waves produced by the singer or acoustic instrument. The computer cannot handle the gradual change of the red waves. The computer should use the approximation shown in the gray shaded area of ​​the figure. This figure is an exaggerated example and does not represent the actual recording.
Converting between analog and digital signals reveals the difference between low-quality and high-quality audio interfaces. The sample rate and sample format control the amount of audio information stored by the computer. The more information that is stored, the better the audio interface can approximate the original microphone signal. The possible sample rates and sample formats determine only a part of the quality of the sound produced or obtained by the audio interface. For example, an audio interface built into the motherboard can support 24-bit sample formats and 192 kHz sample rates. On the other hand, a professional-grade FireWire-connected audio interface with a 16-bit sample format and 44.1 kHz sample rate may sound better.
1.3.1. Shows
A sample is a unit of audio data. The computer stores video data as a series of still images (each called a “frame”) and displays them one at a time at a specified speed (called a “frame rate”). The computer stores audio data as a series of still sound images (each called a “sample”) and plays them back one at a time at a specified frequency (called a “sample rate”).
There are not many types of frame formats and frame rates that are used to store video data. There are many types of sample formats and sample rates that are used to store audio data.

Frequency used for audio (sample rate, PCM, DSD, etc.)

On this occasion, I would like to explain the frequencies used in digital audio and their meanings.

 

 

Recently, the high-resolution sound source has increased, such as 192KHz Toka, 11.2MHz, as the frequency has been written or will, what frequency?

I would like to explain the frequency used for said audio taking as an example the Combo384 installed in the USB-DAC used in LV2.0.

1. 1. What is the sampling frequency?

Music distribution is becoming mainstream these days, but audio was first digitized on CDs, which are still on the market.

You often hear that the sample rate of a CD is 44.1KHz. Since digital signals are basically 0 or 1, to reproduce up to the 20 KHz limit that can be heard by the human ear, a resolution of twice that frequency is required. Furthermore, the frequency was decided to be 44.1 KHz taking into account the digital signal processing margin. Since a musical signal is a set of sine waves, it is 44.1 KHz that can fluctuate at a maximum frequency of 20 KHz.

2. What are 16 bits and 24 bits?

As you may hear often, CDs are sometimes described as 44.1KHz / 16bit. This 16 bit is the volume of the sound. Since 16 bits can express the size of 2 raised to 16, there are 65536 different sizes.

Converting this to dB is 20LOG (65536), which is approximately 96 dB. The dynamic range of a CD (the difference between low and loud sounds) is 96 dB.

For DVD and Hi-Res, it can be 24-bit, but in this case, it’s 16.77 million steps of 144 dB.

3. 3. PCM format

So what is the actual signal? In the case of the PCM format, the standard called I2S, which can support up to 32 bits in sample rate, is common. In the case of a CD, being stereo, the data has a frequency of 44.1 KHz with 2 channels (L, R) alternately 32 bits (although in reality 16 bits are used).

Therefore, to process this digitally, a processing capacity of 44.1KHz x 2CH x 32bit = 2.8224MHz is required.

Bitrate

In communication, it indicates how many bits of data are transferred per hour and is generally expressed in bps (bit / s) of how many bits are transferred (processed) per second.

If it is low, the size when saving as a file is small and there is space on the transmission line for communication. For example, when an audio (1 channel) is compressed to 1/3, the 3 channel audio can be sent at the same bit rate. Excuse the old story, but considering the age of analog communication (analog cell phones), digitizing + compression will support multiple calls with the same radio waves.

Finally
I often hear what is called Hi-Res Audio. The sampling frequency is said to be 96 kHz or 192 kHz, which is above 48 kHz, the number of quantization bits is 24 bits, and the limit (high range) of human hearing is about 20 kHz, but it expresses frequencies higher than that. It will be. It is the same bit rate as the image from a long time ago. .. ..
By the way, it seems that dogs can hear up to 60 kHz and cats up to about 64 kHz.

Hi-Res Example (Hi-Res Audio)
Sampling frequency Number of quantization bits Number of channels bit rate Frequency that can be expressed
192 kHz twenty-four 2 9.216 kbps 96 kHz
192 kHz 16 16 2 6,144 kbps 96 kHz
96 kHz twenty-four 2 4.608 kbps 48 kHz
96 kHz 16 16 2 3,072 kbps 48 kHz
48 kHz twenty-four 2 2,304 kbps 24 kHz
Considering the limit of human hearing (around 20 kHz), according to the sampling theorem, 48 kHz or 44.1 kHz is a sufficient frequency, but what about all of them? .. ..
In my case, I cannot distinguish the high resolution range, but it should be able to reproduce the discarded frequency at 48 kHz to 96 kHz, and when the number of quantization bits is in the 24-bit range, the sound pressure (dB) is a bit. Feels like I’m going up (?) (It’s just my ears).
I’d like to make a comparison if I get a chance, but I feel like I can’t say by ear that I don’t have a proper regenerator (like an expensive analog amp).

Is it finally time for cats and dogs to get verified in the acoustics industry? .. ..

monipet
animal hospital of the dog watch cat stand
safe even at night when leaving the hospital sensor

ASSE / CORPA
, IoT, create new value by leveraging big data
to “be nice when you are”, “you can” in the

Corresponding ECHONET Lite middleware from OSGi
Support fast delivery HEMS development!

GuruPlug
Card Size Smart Server

Co., Ltd. JSP
Yokohama-based software development, systems development,
product development (monipet) and IT company dedicated to agriculture