![\"Bit](\"https:\/\/www.masteringbox.com\/wp-content\/uploads\/2018\/12\/SSampling-1139x550.png\")
<\/p>\n<\/p>\n
\u25a0 Sampling rate
\n(= sample rate)
\nIf it is 44.1 kHz, the data is taken at 44100 times\/sec
\nWavewidth (fineness) = sound pitch Del<\/p>\n
![\"bit](\"http:\/\/www.realhd-audio.com\/wp-content\/uploads\/2014\/05\/140524_ar_graphic.jpg\")
<\/p>\n
sampling theorem (the original can be reproduced by sampling at twice the rate).
\nThe calculation can be sampled up to the audio frequency of 22 kHz.
\nThis is enough because normal CDs only record up to 20 kHz. By the way, I don’t quite understand the<\/p>\n
sampling theorem, but is it true that sampling two points in a cycle and playing between them is an approximation with a sine wave? Addendum: Since the sampling theorem is a theorem about the result of the Fourier transform, the frequency mentioned there is naturally limited to sine waves. The sampling theorem is that “only sine waves less than half the sampling rate (fs) can be sampled”. That’s how it is. \u25a0 Quantization bit (= bit depth) If 16 bits, divide waveform height by 2 ^ 16. Wave height = volume Bit rate is the transfer (processing) speed, in units of bps . It is completely different from the quantization bit. The bit rate will be described later. BTW, quantization is called quantize, but it seems it’s not called quantization bit.<\/p>\n
Speaking of quantizing,
\nit’s like adjusting the timing of the sound in DTM and others.<\/p>\n
Postscript:
\nIt seems that the unit of the vertical axis is not dB. Sound pressure does not appear to be directly equal
\nbecause it becomes a wave when sound is converted to voltage. I don’t know anything because it’s about electricity. hard.<\/p>\n
Bit depth and bit rate<\/p>\n
From Wikipedia.
\nBit rate = (bit depth) * (sample rate) * (number of channels)
\nFor example, if the sample rate is 44.1 kHz, the bit depth is 16 bits, and 2 channels (stereo), the bit rate is as follows:
\n16 * 44100 * 2 = 1411200 bits\/sec = 1411.2 kbps<\/p>\n
bitrate means the amount of data processed per unit of time.<\/p>\n
The example above is for a CD.
\nFor mp3s, the player’s specifications are usually up to 320 kbps.
\nI think this number and 1411.2 kbps are quite different, but since
\nthis bps is the data processing speed after compression
\n, comparing CD bitrate and mp3 bitrate has nothing to do with sound quality. There is a story that
\neven with 192kbps mp3, there seems to be no problem with sound quality, so even professionals can’t tell it apart from wav . I personally haven’t heard or compared so I don’t know. Maybe it’s the type that doesn’t bother me even though the recording quality is pretty bad.<\/p>\n
known specifications<\/p>\n
\u25a0
\nCD sample rate 44.1kHz
\nvoice frequency band 20Hz ~ 20kHz
\ndynamic range 96dB (= 1bit 6dB * 16bit)<\/p>\n
\u25a0
\nDVD Audio Sample Rate 48kHz, 96kHz,
\n192kHz voice frequency band ~ 88kHz (192kHz)
\ndynamic range of approximately 146dB (quantization bit 24bit ) )<\/p>\n
Where is the 96db range centered?
\nThat may be strange, but
\n0db is not quiet (my left ear hearing is -5db at 4kHz), so
\ncould be extreme story -96db~0db right?
\nI wonder if it’s a mixer or a producer’s favourite.<\/p>\n
Also, even if the range is 96 db,
\nit may not be possible to play all around the headphones.
\nI think I need a proper woofer.<\/p>\n
from now on<\/p>\n
After researching so far, I became interested in lossless!
\nI often watch it on FLAC or Apple Lossless.
\nIt may be time to finally understand Huffman coding<\/p>\n","protected":false},"excerpt":{"rendered":"